Copper becomes green when exposed to moist air for a long period. This is due to
- Athe formation of a layer of cupric oxide on the surface of copper.
- Bthe formation of a layer of basic carbonate of copper on the surface of copper.
- Cthe formation of a layer of cupric hydroxide on the surface of copper.
- Dthe formation of basic copper sulphate layer on the surface of the metal.
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Similar Questions
What products are formed when $1 \ mol$ of calcium phosphide reacts with an excess of water?
Medium
View SolutionMatch column-$I$ with column-$II$ :
column-$I$ column-$II$ $a$. $Ra$ $p$. Aeroplane industry $b$. $K$ $q$. Down cell $c$. $Li$ $r$. Photo electric cell $d$. $Na$ $s$. Radioactive
| column-$I$ | column-$II$ |
| $a$. $Ra$ | $p$. Aeroplane industry |
| $b$. $K$ | $q$. Down cell |
| $c$. $Li$ | $r$. Photo electric cell |
| $d$. $Na$ | $s$. Radioactive |
Medium
View Solution$A$ pink colored salt on dry heating becomes blue in colour. The salt may contain:
Easy
View SolutionSelect the incorrect order for the given properties:
$(a)$ $A_2B < AB < A_2B_3 = \text{Lattice Energy (L.E.)}$ (Charge of $B = -2$)
$(b)$ $Na_2CO_3 < K_2CO_3 < Rb_2CO_3 < Cs_2CO_3 = \text{Thermal stability}$
$(c)$ $MgF_2 < CaF_2 < SrF_2 < BaF_2 < BeF_2 = \text{Solubility}$
$(d)$ $LiOH < NaOH < KOH < RbOH < CsOH = \text{Solubility and stability}$
$(a)$ $A_2B < AB < A_2B_3 = \text{Lattice Energy (L.E.)}$ (Charge of $B = -2$)
$(b)$ $Na_2CO_3 < K_2CO_3 < Rb_2CO_3 < Cs_2CO_3 = \text{Thermal stability}$
$(c)$ $MgF_2 < CaF_2 < SrF_2 < BaF_2 < BeF_2 = \text{Solubility}$
$(d)$ $LiOH < NaOH < KOH < RbOH < CsOH = \text{Solubility and stability}$
Difficult
View SolutionMatch List-$I$ with List-$II$.
List-$I$ List-$II$ $A$. Chlorophyll $I$. $Na_2CO_3$ $B$. Soda ash $II$. $CaSO_4$ $C$. Dentistry,Ornamental work $III$. $Mg^{2+}$ $D$. Used in white washing $IV$. $Ca(OH)_2$
Choose the correct answer from the options given below:
| List-$I$ | List-$II$ |
|---|---|
| $A$. Chlorophyll | $I$. $Na_2CO_3$ |
| $B$. Soda ash | $II$. $CaSO_4$ |
| $C$. Dentistry,Ornamental work | $III$. $Mg^{2+}$ |
| $D$. Used in white washing | $IV$. $Ca(OH)_2$ |
Choose the correct answer from the options given below:
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