Copper sulphate solution reacts with KCN to g | vedclass

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Question

(D) The reaction of copper sulphate with potassium cyanide proceeds in steps:$1$. $CuSO_4 + 2KCN 	o Cu(CN)_2 + K_2SO_4$$2$. The unstable $Cu(CN)_2$ d

Vedclass · Accepted Answer

$K_3[Cu(CN)_4]$

Vedclass · Answer

(D) The reaction of copper sulphate with potassium cyanide proceeds in steps:$1$. $CuSO_4 + 2KCN 	o Cu(CN)_2 + K_2SO_4$$2$. The unstable $Cu(CN)_2$ decomposes to give $Cu_2(CN)_2$ and cyanogen gas: $2Cu(CN)_2 	o Cu_2(CN)_2 + (CN)_2$$3$. $Cu_2(CN)_2$ then reacts with excess $KCN$ to form the stable complex potassium tetracyanocuprate$(I)$: $Cu_2(CN)_2 + 6KCN 	o 2K_3[Cu(CN)_4]$Thus,the final product is $K_3[Cu(CN)_4]$.

Copper sulphate solution reacts with $KCN$ to give

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