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(C) Acidity is determined by the stability of the conjugate base formed after the loss of a proton $(H^+)$. Electron-withdrawing groups $(EWG)$ stabil

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$4	ext{-chlorophenol} < 4	ext{-fluorophenol}$

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(C) Acidity is determined by the stability of the conjugate base formed after the loss of a proton $(H^+)$. Electron-withdrawing groups $(EWG)$ stabilize the conjugate base through the inductive effect ($-I$ effect),thereby increasing acidity.$(A)$ $CF_3OH$ is more acidic than $CCl_3OH$ because $F$ is more electronegative than $Cl$,exerting a stronger $-I$ effect.$(B)$ $CHF_3$ is more acidic than $CHCl_3$ because $F$ is more electronegative than $Cl$,stabilizing the carbanion formed after deprotonation.$(C)$ In $4	ext{-fluorophenol}$,the $F$ atom exerts a strong $-I$ effect,which stabilizes the phenoxide ion more effectively than the $Cl$ atom in $4	ext{-chlorophenol}$. Thus,$4	ext{-chlorophenol} $(D)$ $F_3C-CO_2H$ is more acidic than $Cl_3C-CO_2H$ due to the stronger $-I$ effect of the $CF_3$ group compared to the $CCl_3$ group.All options provided represent correct acidity orders based on the $-I$ effect.

Which of the following represents the correct order of acidity?

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