The correct order of S_{N}1 reaction rate for | vedclass

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Question

(C) The rate of $S_{N}1$ reaction depends on the stability of the carbocation intermediate formed after the departure of the leaving group $(Cl^-)$.$(

Vedclass · Accepted Answer

$i > iii > ii$

Vedclass · Answer

(C) The rate of $S_{N}1$ reaction depends on the stability of the carbocation intermediate formed after the departure of the leaving group $(Cl^-)$.$(i)$ Forms an allylic carbocation,which is resonance stabilized.(ii) Forms a secondary $(2^{\circ})$ cyclohexyl carbocation.(iii) Forms a tertiary $(3^{\circ})$ carbocation.Comparing the stability of these carbocations:$1$. The allylic carbocation (from $i$) is highly stable due to resonance.$2$. The tertiary carbocation (from $iii$) is stable due to inductive effect and hyperconjugation.$3$. The secondary carbocation (from $ii$) is the least stable among the three.Thus,the order of stability of carbocations is $i > iii > ii$. Consequently,the order of $S_{N}1$ reactivity is $i > iii > ii$. However,based on standard textbook problems of this type,the resonance-stabilized allylic carbocation is significantly more reactive. Given the options,$i > iii > ii$ is the correct chemical trend.

The correct order of $S_{N}1$ reaction rate for the given compounds is:

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