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(C) $1$. The reaction of cyclohexene with $HOCl$ (hypochlorous acid) proceeds via the formation of a chloronium ion intermediate,followed by the attac

Vedclass · Accepted Answer

$A = 	ext{trans-2-chlorocyclohexanol}$,$B = 	ext{cyclohexene oxide}$

Vedclass · Answer

(C) $1$. The reaction of cyclohexene with $HOCl$ (hypochlorous acid) proceeds via the formation of a chloronium ion intermediate,followed by the attack of water (nucleophile) from the side opposite to the chlorine atom. This results in the formation of $trans-2-chlorocyclohexanol$ as product $(A)$.$2$. In the presence of a base like $NaOH$,the $trans-2-chlorocyclohexanol$ undergoes an intramolecular $S_N2$ reaction. The hydroxyl group is deprotonated to form an alkoxide ion,which then attacks the carbon atom bearing the chlorine atom from the backside,displacing the chloride ion. This process is facilitated by Neighbouring Group Participation ($N$.$G$.$P$.).$3$. This intramolecular cyclization leads to the formation of $cyclohexene oxide$ (an epoxide) as product $(B)$.

The correct statement about the reaction shown above is:

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