Correct statements regarding alkyl halides ($R-X$) among the following are:
A. Alcohol being less polar solvent as compared to water, alcoholic $KOH$ favours elimination reaction with $R-X$.
B. Order of reactivity towards $S_N1$ mechanism is $C_6H_5-CH_2-Cl > C_6H_5-CHCl-C_6H_5$.
C. Non substituted aryl halides exhibit properties similar to alkyl halides.
D. Vinyl chloride is an example of haloalkene and allyl chloride is an example of haloalkyne.
E. $R-Cl$ can be prepared by reacting $R-OH$ with $SOCl_2$ but $Ar-Cl$ cannot be prepared by reacting $Ar-OH$ with $SOCl_2$.
Choose the correct answer from the options given below:
- AA, B and C Only
- BB and D Only
- CA and E Only
- DD and E Only
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Similar Questions
What will be the final major product?
Identify the major product formed from the following reaction sequence:
The product $(X)$ is:
Difficult
View SolutionMatch the reactants in Column-$I$ with their products in Column-$II$.
Column-$I$ (Reactants) Column-$II$ (Products) $A$. $H_2C=CH_2 + Br_2 \xrightarrow{CCl_4}$ $i$. $CH_3CH_2CH_2Br$ $B$. $CH_3CH=CH_2 + HI \rightarrow$ $ii$. $BrCH_2-CH_2Br$ $C$. $C_6H_5N_2^+X^- + KI \rightarrow$ $iii$. $CH_3CHICH_3$ $D$. $CH_3CH=CH_2 + HBr \xrightarrow{peroxide}$ $iv$. $C_6H_5I$
| Column-$I$ (Reactants) | Column-$II$ (Products) |
| $A$. $H_2C=CH_2 + Br_2 \xrightarrow{CCl_4}$ | $i$. $CH_3CH_2CH_2Br$ |
| $B$. $CH_3CH=CH_2 + HI \rightarrow$ | $ii$. $BrCH_2-CH_2Br$ |
| $C$. $C_6H_5N_2^+X^- + KI \rightarrow$ | $iii$. $CH_3CHICH_3$ |
| $D$. $CH_3CH=CH_2 + HBr \xrightarrow{peroxide}$ | $iv$. $C_6H_5I$ |
Medium
View SolutionMatch the reactions given in Column-$I$ with the types of reactions given in Column-$II$.
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