The current I versus time t graph for a condu | vedclass

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(D) The total charge $\Delta q$ flowing through the conductor is equal to the area under the $I-t$ graph.The area of the triangle is given by:$\Delta

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(D) The total charge $\Delta q$ flowing through the conductor is equal to the area under the $I-t$ graph.The area of the triangle is given by:$\Delta q = 	ext{Area} = \frac{1}{2} 	imes 	ext{base} 	imes 	ext{height}$$\Delta q = \frac{1}{2} 	imes 15 \, s 	imes 10 \, A = 75 \, C$The average current $I_{	ext{avg}}$ is defined as the total charge divided by the total time interval:$I_{	ext{avg}} = \frac{\Delta q}{\Delta t} = \frac{75 \, C}{15 \, s} = 5 \, A$Therefore,the correct option is $D$.

The current $I$ versus time $t$ graph for a conductor is shown in the figure. The average current through the conductor in the interval $0$ to $15 \, s$ is ............ $A$.

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