Current in a circuit falls from 5.0 , A to 0. | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Initial current,$I_{1} = 5.0 \, A$.Final current,$I_{2} = 0 \, A$.Change in current,$di = I_{1} - I_{2} = 5.0 \, A$.Time taken for the change,$dt

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(B) Initial current,$I_{1} = 5.0 \, A$.Final current,$I_{2} = 0 \, A$.Change in current,$di = I_{1} - I_{2} = 5.0 \, A$.Time taken for the change,$dt = 0.1 \, s$.Average $emf$,$e = 200 \, V$.For self-inductance $(L)$ of the circuit,the relation for average $emf$ is given by:$e = L \frac{di}{dt}$Rearranging for $L$:$L = e \cdot \frac{dt}{di}$Substituting the values:$L = 200 \cdot \frac{0.1}{5.0} = 200 \cdot 0.02 = 4 \, H$.Hence,the self-inductance of the circuit is $4 \, H$.

Current in a circuit falls from $5.0 \, A$ to $0.0 \, A$ in $0.1 \, s$. If an average $emf$ of $200 \, V$ is induced,give an estimate of the self-inductance of the circuit in $H$.

Similar Questions

When the current in a coil changes from $8 \ A$ to $2 \ A$ in $3 \times 10^{-3} \ s$,the induced $e.m.f.$ in the coil is $2 \ V$. The self-inductance of the coil in millihenry $(mH)$ is:

The self-induced $emf$ of a coil is $25\,V$. When the current in it is changed at a uniform rate from $10\,A$ to $25\,A$ in $1\,s$,the change in the energy stored in the inductor is......$J$.

The current in a coil of inductance $0.2 \,H$ changes from $5 \,A$ to $2 \,A$ in $0.5 \,s$. The magnitude of the average induced emf in the coil is (in $\,V$)

$A$ solenoid is connected to a battery so that a steady current flows through it. If an iron core is inserted into the solenoid,the current will

In a coil,current falls from $5\, A$ to $0\, A$ in $0.2\, s$. If an average $emf$ of $150\, V$ is induced,then the self-inductance of the coil is.....$H$

Vedclass Test Series

Exam Paper Generator

Online Exam Module