(D) The molecule $A$ is benzene $(C_6H_6)$.In benzene,all carbon atoms are $sp^2$ hybridized.$sp^2$ hybridized carbon atoms have a trigonal planar geo

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(D) The molecule $A$ is benzene $(C_6H_6)$.In benzene,all carbon atoms are $sp^2$ hybridized.$sp^2$ hybridized carbon atoms have a trigonal planar geometry with a bond angle of $120^{\circ}$.The carbon-carbon bond length in benzene is $1.39 \ \mathring{A}$,which is intermediate between a single bond $(1.54 \ \mathring{A})$ and a double bond $(1.34 \ \mathring{A})$.Therefore,the $C-C$ bond angle is $120^{\circ}$.

Class 11 Chemistry Data Entry - Chemistry Level 0 of all question bank

Cyclic hydrocarbon molecule $A$ has all the carbon and hydrogen atoms in a single plane. All the carbon-carbon bonds are of the same length,which is less than $1.54 \ \mathring{A}$ but more than $1.34 \ \mathring{A}$. The $C-C$ bond angle will be

AIPMT 1989 All AIPMT

A
$109^{\circ}28'$
B
$100^{\circ}$
C
$180^{\circ}$
D
$120^{\circ}$

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Cyclic hydrocarbon molecule $A$ has all the carbon and hydrogen atoms in a single plane. All the carbon-carbon bonds are of the same length,which is less than $1.54 \ \mathring{A}$ but more than $1.34 \ \mathring{A}$. The $C-C$ bond angle will be

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If the pair of lines given by $(x^2+y^2) \cos^2 \theta = (x \cos \theta + y \sin \theta)^2$ are perpendicular to each other,then $\theta$ is equal to

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