Cyclohexylamine when treated with nitrous aci | vedclass

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Question

(B) $1$. Cyclohexylamine $(C_6H_{11}NH_2)$ reacts with nitrous acid $(HNO_2)$ to form cyclohexanol $(P)$ $(C_6H_{11}OH)$.$2$. Cyclohexanol $(P)$ on ox

Vedclass · Accepted Answer

Vedclass · Answer

(B) $1$. Cyclohexylamine $(C_6H_{11}NH_2)$ reacts with nitrous acid $(HNO_2)$ to form cyclohexanol $(P)$ $(C_6H_{11}OH)$.$2$. Cyclohexanol $(P)$ on oxidation with $PCC$ (Pyridinium chlorochromate) gives cyclohexanone $(Q)$ $(C_6H_{10}O)$.$3$. Cyclohexanone $(Q)$ undergoes an aldol condensation reaction when heated with dilute $NaOH$ to form the final product $(R)$. The reaction involves the formation of a $\beta$-hydroxy ketone which then undergoes dehydration to form an $\alpha,\beta$-unsaturated ketone. The product $(R)$ is $2$-cyclohexylidenecyclohexanone.

Cyclohexylamine when treated with nitrous acid yields $(P)$. On treating $(P)$ with $PCC$ results in $(Q)$. When $(Q)$ is heated with dilute $NaOH$,we get $(R)$. The final product $(R)$ is:

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