(A) The cyclopentadienyl anion $(C_5H_5^-)$ has a cyclic structure with $sp^2$ hybridized carbon atoms,making it planar. It contains $6 \pi$-electrons

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(A) The cyclopentadienyl anion $(C_5H_5^-)$ has a cyclic structure with $sp^2$ hybridized carbon atoms,making it planar. It contains $6 \pi$-electrons ($4$ from the two double bonds and $2$ from the lone pair on the negatively charged carbon),which follows $H$ückel's rule ($4n + 2 = 6$,where $n = 1$). Therefore,it is aromatic.

Class 11 Chemistry Hydrocarbons Aromatic hydrocarbon

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The cyclopentadienyl anion is:

A
Aromatic
B
Non-aromatic
C
Non-planar
D
Aliphatic

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Class 11

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Hydrocarbons

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Aromatic hydrocarbon

Among the following compounds $(I-III)$,the correct order of reactivity towards electrophilic substitution reaction is:

MediumAIPMT 1997

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$x =$ Number of aromatic compounds obtained when the above compound undergoes complete acidic hydrolysis.

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Product $(B)$ in the above reaction is

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The major product formed in the reaction is:
$Isopropylbenzene + HNO_3 \xrightarrow{conc. H_2SO_4} ?$

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The major products $P$ and $Q$ formed in the following reaction schemes are:

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The cyclopentadienyl anion is:

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Among the following compounds $(I-III)$,the correct order of reactivity towards electrophilic substitution reaction is:

$x =$ Number of aromatic compounds obtained when the above compound undergoes complete acidic hydrolysis.

Product $(B)$ in the above reaction is

The major product formed in the reaction is:$Isopropylbenzene + HNO_3 \xrightarrow{conc. H_2SO_4} ?$

The major products $P$ and $Q$ formed in the following reaction schemes are:

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The major product formed in the reaction is:
$Isopropylbenzene + HNO_3 \xrightarrow{conc. H_2SO_4} ?$