Cyclopentanol on reaction with NaH followed b | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The reaction of cyclopentanol with $NaH$ forms a sodium alkoxide intermediate. This alkoxide then reacts with $CS_{2}$ to form a sodium xanthate s

Vedclass · Accepted Answer

xanthate

Vedclass · Answer

(D) The reaction of cyclopentanol with $NaH$ forms a sodium alkoxide intermediate. This alkoxide then reacts with $CS_{2}$ to form a sodium xanthate salt. Finally, the reaction with $CH_{3}I$ (methyl iodide) results in the formation of a methyl xanthate ester. This sequence is known as the Chugaev elimination precursor synthesis. Therefore, the product is a xanthate. Thus, option $(d)$ is the correct answer.

Cyclopentanol on reaction with $NaH$ followed by $CS_{2}$ and $CH_{3}I$ produces a/an

Similar Questions

Which among the following has the highest boiling point?

Which of the following would undergo dehydration most readily?

$CH \equiv CH$ $\xrightarrow{Hg^{2+}/H_2SO_4} B$ $\xrightarrow{CH_3MgX/H_2O} C$ $\xrightarrow{[O]} D$. What is the final product $D$?

Which of the following compounds will give the most stable carbonium ion during dehydration?

Consider the following reaction sequence:
$C_6H_5-CH=CH-CHO$ $\xrightarrow[35^{\circ}C]{LiAlH_4} A$ $\xrightarrow[Excess]{CH_3MgBr} B$
Identify $B$ in the reaction.

Vedclass Test Series

Exam Paper Generator

Online Exam Module