Define the amplitude of $SHM$.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) The amplitude of $SHM$ (Simple Harmonic Motion) is defined as the maximum displacement of the oscillating particle from its mean or equilibrium position.
It represents the extent of the motion on either side of the equilibrium point.
Mathematically,if the displacement of a particle in $SHM$ is given by $x(t) = A \sin(\omega t + \phi)$,then $A$ is the amplitude of the motion.
The $SI$ unit of amplitude is the meter $(m)$.

Explore More

Similar Questions

For particle $P$ revolving around the centre $O$ with radius of circular path $r$ and angular velocity $\omega$,as shown in the figure,the projection of $OP$ on the $x$-axis at time $t$ is .................

The displacement of a particle varies according to the relation $x = 3 \sin 100t + 8 \cos^2 50t$. Which of the following is/are correct about this motion?

Obtain the expression of displacement from the force law for simple harmonic motion.

Difficult
View Solution

$A$ particle moves in $S.H.M.$ such that its acceleration is $a = -px$,where '$x$' is the displacement of the particle from the equilibrium position and '$p$' is a constant. The period of oscillation is

The motion of the particle is given by the equation $x = A \sin \omega t + B \cos \omega t$. The motion of the particle is:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo