Dehydrogenation of CH_3-CH(OH)-CH_3 gives | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Dehydrogenation of a secondary alcohol like isopropyl alcohol $(CH_3-CH(OH)-CH_3)$ involves the removal of hydrogen in the presence of a catalyst

Vedclass · Accepted Answer

Acetone

Vedclass · Answer

(A) Dehydrogenation of a secondary alcohol like isopropyl alcohol $(CH_3-CH(OH)-CH_3)$ involves the removal of hydrogen in the presence of a catalyst like copper at $573 \ K$. The reaction is: $CH_3-CH(OH)-CH_3 \xrightarrow{Cu, 573 \ K} CH_3-CO-CH_3 + H_2$. This results in the formation of a ketone,which is acetone $(CH_3-CO-CH_3)$.

Dehydrogenation of $CH_3-CH(OH)-CH_3$ gives

Similar Questions

The boiling point of glycerol is higher than that of propanal because of:

The product $(A)$ is:

The correct order of boiling point for primary $({1^o}),$ secondary $({2^o}),$ and tertiary $({3^o})$ alcohols is

Treatment of a $2^{\circ} \text{ alcohol}$ with $CrO_3/H_2SO_4$ yields a/an

Ethylene glycol,on oxidation with periodic acid $(HIO_4)$,gives:

Vedclass Test Series

Exam Paper Generator

Online Exam Module