Describe the change in hybridization (if any) of the $Al$ atom in the following reaction:
$AlCl_3 + Cl^{-} \to AlCl_4^-$
$AlCl_3 + Cl^{-} \to AlCl_4^-$
(N/A) In the gaseous state,$AlCl_3$ exists as a dimer $Al_2Cl_6$,where each $Al$ atom is $sp^3$ hybridized.
In the reaction $AlCl_3 + Cl^{-} \to AlCl_4^-$,the $Al$ atom in the product $AlCl_4^-$ also exhibits $sp^3$ hybridization.
Therefore,there is no change in the hybridization of the $Al$ atom during this reaction.
In the reaction $AlCl_3 + Cl^{-} \to AlCl_4^-$,the $Al$ atom in the product $AlCl_4^-$ also exhibits $sp^3$ hybridization.
Therefore,there is no change in the hybridization of the $Al$ atom during this reaction.
Explore More
Similar Questions
The molecule in which the central atom does $NOT$ undergo $sp^3$ hybridisation is
Which orbital is more electronegative among $sp$,$sp^2$,and $sp^3$? Why?
Medium
View Solution$sp^3$ hybridized nitrogen is present in
Medium
View SolutionThe hybridization of $P$ exhibited in $PF_{5}$ is $sp^{x}d^{y}$. The value of $y$ is $...$
The $sp^3d^2$ hybridization of the central atom of a molecule leads to which geometry?
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo