Determine the order and degree (if defined) o | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The given differential equation is $\left(\frac{ds}{dt}\right)^{4} + 3s \frac{d^{2}s}{dt^{2}} = 0$. The highest order derivative present in the eq

Vedclass · Accepted Answer

$2, 1$

Vedclass · Answer

(A) The given differential equation is $\left(\frac{ds}{dt}\right)^{4} + 3s \frac{d^{2}s}{dt^{2}} = 0$. The highest order derivative present in the equation is $\frac{d^{2}s}{dt^{2}}$. Since the highest order derivative is of the second order,the order of the differential equation is $2$. The degree of a differential equation is the power of the highest order derivative when the equation is expressed as a polynomial in terms of its derivatives. The highest order derivative $\frac{d^{2}s}{dt^{2}}$ has an exponent of $1$. Therefore,the degree of the differential equation is $1$.

Determine the order and degree (if defined) of the differential equation $\left(\frac{ds}{dt}\right)^{4} + 3s \frac{d^{2}s}{dt^{2}} = 0$.

Similar Questions

The order and degree of the differential equation $3 - (\frac{d^3 y}{d x^3})^{\frac{7}{3}} = (\frac{dy}{d x})^5$ are respectively:

Which of the following differential equations has the same order and degree?

The order of the differential equation of all parabolas having their directrix parallel to the $x$-axis is

The order and degree of the differential equation $3 - (\frac{d^3y}{dx^3})^{2/3} = (\frac{dy}{dx})^5$ are respectively

The order and degree of the differential equation $\sqrt{1 + \frac{1}{(\frac{dy}{dx})^2}} = (\frac{d^2y}{dx^2})^{\frac{3}{2}}$ are ...

Vedclass Test Series

Exam Paper Generator

Online Exam Module