Determine the absolute configurations of the | vedclass

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(A) To determine the absolute configuration ($R$ or $S$) of the chiral centers,we assign priorities to the groups attached to the chiral carbon using

Vedclass · Accepted Answer

$a = R; b = R$

Vedclass · Answer

(A) To determine the absolute configuration ($R$ or $S$) of the chiral centers,we assign priorities to the groups attached to the chiral carbon using Cahn-Ingold-Prelog $(CIP)$ rules.For carbon $(a)$: The groups are $-Cl$ (priority $1$),the rest of the ring towards carbon $(b)$ (priority $2$),the rest of the ring towards carbon $(5)$ (priority $3$),and $-H$ (priority $4$). Since the $-H$ is on a wedge (or effectively pointing towards us in this projection),the clockwise direction corresponds to $R$.For carbon $(b)$: The groups are $-Cl$ (priority $1$),the rest of the ring towards carbon $(6)$ (priority $2$),the rest of the ring towards carbon $(2)$ (priority $3$),and $-H$ (priority $4$). Following the $CIP$ rules,the configuration is determined to be $R$.Thus,both carbons $(a)$ and $(b)$ have the $R$ configuration.

$A$. Acetaldehyde,vinyl alcohol	$1$. Enantiomers
$B$. Eclipsed and staggered ethane	$2$. Tautomers
$C$. $(+)2$-butanol,$(-)2$-butanol	$3$. Chain isomers
$D$. Methyl-$n$-propylamine and diethylamine	$4$. Conformational isomers
	$5$. Metamers

Determine the absolute configurations of the labeled carbons ($a$ and $b$).

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Match the following:
$A$. Acetaldehyde,vinyl alcohol $1$. Enantiomers
$B$. Eclipsed and staggered ethane $2$. Tautomers
$C$. $(+)2$-butanol,$(-)2$-butanol $3$. Chain isomers
$D$. Methyl-$n$-propylamine and diethylamine $4$. Conformational isomers
$5$. Metamers

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