Determine which of the following polynomials has $(x + 1)$ as a factor: $x^{4} + 3x^{3} + 3x^{2} + x + 1$.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(NONE) According to the Factor Theorem,$(x + 1)$ is a factor of a polynomial $p(x)$ if and only if $p(-1) = 0$.
Let $p(x) = x^{4} + 3x^{3} + 3x^{2} + x + 1$.
Substitute $x = -1$ into the polynomial:
$p(-1) = (-1)^{4} + 3(-1)^{3} + 3(-1)^{2} + (-1) + 1$
$p(-1) = 1 + 3(-1) + 3(1) - 1 + 1$
$p(-1) = 1 - 3 + 3 - 1 + 1$
$p(-1) = 1$
Since $p(-1) = 1 \neq 0$,by the Factor Theorem,$(x + 1)$ is not a factor of the given polynomial.

Explore More

Similar Questions

Write the coefficients of $x^2$ in each of the following:
$(i)$ $2+x^2+x$
$(ii)$ $2-x^2+x^3$

Factorise the following using appropriate identities : $4 y^{2}-4 y+1$

Factorise : $x^{3}-3 x^{2}-9 x-5$

Difficult
View Solution

Find the value of the polynomial $5x - 4x^2 + 3$ at $x = -1$.

Give one example each of a binomial of degree $35$ and of a monomial of degree $100$.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo