(A) We know that the diagonals of a parallelogram bisect each other at their point of intersection.Since $O$ is the intersection point,$AC = 2 \times

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(A) We know that the diagonals of a parallelogram bisect each other at their point of intersection.Since $O$ is the intersection point,$AC = 2 \times OA$ and $BD = 2 \times OD$.Given $OA = 3\, cm$ and $OD = 2\, cm$.Therefore,$AC = 2 \times 3\, cm = 6\, cm$.And $BD = 2 \times 2\, cm = 4\, cm$.Hence,the lengths of $AC$ and $BD$ are $6\, cm$ and $4\, cm$ respectively.

Class 9 Mathematics Quadrilaterals Mix Examples - Quadrilaterals

Medium

Diagonals $AC$ and $BD$ of a parallelogram $ABCD$ intersect each other at $O$. If $OA = 3\, cm$ and $OD = 2\, cm$,determine the lengths of $AC$ and $BD$.

A
$AC = 6\, cm, BD = 4\, cm$
B
$AC = 3\, cm, BD = 2\, cm$
C
$AC = 4\, cm, BD = 6\, cm$
D
$AC = 5\, cm, BD = 5\, cm$

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Mix Examples - Quadrilaterals

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Diagonals $AC$ and $BD$ of a parallelogram $ABCD$ intersect each other at $O$. If $OA = 3\, cm$ and $OD = 2\, cm$,determine the lengths of $AC$ and $BD$.

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In parallelogram $PQRS$,diagonal $PR$ bisects $\angle P$. Prove that diagonal $PR$ bisects $\angle R$ also and $PQRS$ is a rhombus.

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