Diameter of a steel ball is measured using a Vernier callipers which has divisions of $0.1\,cm$ on its main scale $(MS)$ and $10$ divisions of its vernier scale $(VS)$ match $9$ divisions on the main scale. Three such measurements for a ball are given as:
$S$.No. $MS\;(cm)$ $VS$ divisions $(1)$ $0.5$ $8$ $(2)$ $0.5$ $4$ $(3)$ $0.5$ $6$
If the zero error is $-0.03\,cm,$ then the mean corrected diameter is ........... $cm$.
| $S$.No. | $MS\;(cm)$ | $VS$ divisions |
| $(1)$ | $0.5$ | $8$ |
| $(2)$ | $0.5$ | $4$ |
| $(3)$ | $0.5$ | $6$ |
If the zero error is $-0.03\,cm,$ then the mean corrected diameter is ........... $cm$.
- A$0.52$
- B$0.59$
- C$0.56$
- D$0.53$
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