(C) The limit of resolution $(\Delta\theta)$ of a telescope is given by the formula: $\Delta\theta = \frac{1.22 \lambda}{d}$Given:$\lambda = 600\, nm

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(C) The limit of resolution $(\Delta\theta)$ of a telescope is given by the formula: $\Delta\theta = \frac{1.22 \lambda}{d}$Given:$\lambda = 600\, nm = 600 \times 10^{-9}\, m$$d = 250\, cm = 2.5\, m$Substituting the values:$\Delta\theta = \frac{1.22 \times 600 \times 10^{-9}}{2.5}$$\Delta\theta = \frac{732 \times 10^{-9}}{2.5}$$\Delta\theta = 292.8 \times 10^{-9}\, rad = 2.928 \times 10^{-7}\, rad$This value is closest to $3.0 \times 10^{-7}\, rad$.

Class 12 Physics Wave Optics Resolving power-Human eye, Microscopes and Telescopes

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The diameter of the objective lens of a telescope is $250\, cm$. For light of wavelength $600\, nm$ coming from a distant object, the limit of resolution of the telescope is close to:

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A
$1.5 \times 10^{-7}\, rad$
B
$2.0 \times 10^{-7}\, rad$
C
$3.0 \times 10^{-7}\, rad$
D
$4.5 \times 10^{-7}\, rad$

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The diameter of the objective lens of a telescope is $250\, cm$. For light of wavelength $600\, nm$ coming from a distant object, the limit of resolution of the telescope is close to:

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