The dimensional formula M L^{-1} T^{-2} does | vedclass

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Question

(C) The dimensional formula for $Young's  modulus$,$Stress$,and $Pressure$ is given by $\frac{Force}{Area} = \frac{[MLT^{-2}]}{[L^2]} = [ML^{-1}T^{-2}

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Strain

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(C) The dimensional formula for $Young's  modulus$,$Stress$,and $Pressure$ is given by $\frac{Force}{Area} = \frac{[MLT^{-2}]}{[L^2]} = [ML^{-1}T^{-2}]$.$Strain$ is defined as the ratio of change in dimension to the original dimension,i.e.,$Strain = \frac{\Delta L}{L}$.Since $Strain$ is a ratio of two similar physical quantities,it is a dimensionless quantity,represented as $[M^0 L^0 T^0]$.Therefore,the dimensional formula $ML^{-1}T^{-2}$ does not represent $Strain$.

Column-$1$	Column-$2$
$(a)$ Wave vector	$(i)$ $M^1L^0T^{-3}$
$(b)$ Linear mass density	$(ii)$ $M^1L^{-1}T^{-2}$
$(c)$ Intensity of a wave	$(iii)$ $M^0L^{-1}T^0$
$(d)$ Volume elasticity coefficient	$(iv)$ $M^1L^{-1}T^0$

The dimensional formula $M L^{-1} T^{-2}$ does not represent which of the following physical quantities?

Similar Questions

$A$ dimensionless quantity

Which of the following pairs has the same dimensions?

Match Column-$1$ with Column-$2$.
Column-$1$ Column-$2$
$(a)$ Wave vector $(i)$ $M^1L^0T^{-3}$
$(b)$ Linear mass density $(ii)$ $M^1L^{-1}T^{-2}$
$(c)$ Intensity of a wave $(iii)$ $M^0L^{-1}T^0$
$(d)$ Volume elasticity coefficient $(iv)$ $M^1L^{-1}T^0$

In $SI$ units,the dimensions of $\sqrt {\frac{{{\varepsilon _0}}}{{{\mu _0}}}} $ are:

What is the dimension of a physical quantity? Explain using a suitable example.

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