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(D) The resistance $R$ of a conductor is given by the formula $R = \rho \frac{l}{A}$,where $\rho$ is the resistivity (specific resistance),$l$ is the

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$3 	imes 10^{-3} \, \Omega$

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(D) The resistance $R$ of a conductor is given by the formula $R = ho \frac{l}{A}$,where $ho$ is the resistivity (specific resistance),$l$ is the length,and $A$ is the cross-sectional area.Given dimensions are $1 \, cm 	imes 1 \, cm 	imes 100 \, cm$.For the resistance between the two square faces $(1 \, cm 	imes 1 \, cm)$,the current flows through the length of $100 \, cm$.Thus,$l = 100 \, cm = 1 \, m$.The area of the square face is $A = 1 \, cm 	imes 1 \, cm = 1 \, cm^2 = 10^{-4} \, m^2$.The resistivity is $ho = 3 	imes 10^{-7} \, \Omega \cdot m$.Substituting these values into the formula:$R = (3 	imes 10^{-7} \, \Omega \cdot m) 	imes \frac{1 \, m}{10^{-4} \, m^2} = 3 	imes 10^{-7} 	imes 10^4 \, \Omega = 3 	imes 10^{-3} \, \Omega$.

Dimensions of a block are $1 \, cm \times 1 \, cm \times 100 \, cm$. If the specific resistance of its material is $3 \times 10^{-7} \, \Omega \cdot m$,the resistance between the square faces is:

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