Dimensions of magnetic field intensity are:

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(C) The magnetic force $F$ on a current-carrying wire is given by $F = I L B \sin 	heta$.Rearranging for the magnetic field intensity $B$,we get $B =

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$[M L^0 T^{-2} A^{-1}]$

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(C) The magnetic force $F$ on a current-carrying wire is given by $F = I L B \sin 	heta$.Rearranging for the magnetic field intensity $B$,we get $B = \frac{F}{I L}$.The dimensional formula for force $F$ is $[M L T^{-2}]$.The dimensional formula for current $I$ is $[A]$.The dimensional formula for length $L$ is $[L]$.Substituting these into the formula: $B = \frac{[M L T^{-2}]}{[A] [L]} = [M L^0 T^{-2} A^{-1}]$.Thus,the correct option is $C$.

Column-$I$	Column-$II$
$(1)$ Torque	$(a)$ $M^1L^1T^{-1}$
$(2)$ Angular momentum	$(b)$ $M^1L^2T^{-1}$
$(3)$ Linear momentum	$(c)$ $M^1L^2T^{-2}$

Similar Questions

Match the physical quantities in Column-$I$ with their corresponding dimensional formulas in Column-$II$.

Column-$I$ Column-$II$

$(1)$ Torque $(a)$ $M^1L^1T^{-1}$

$(2)$ Angular momentum $(b)$ $M^1L^2T^{-1}$

$(3)$ Linear momentum $(c)$ $M^1L^2T^{-2}$

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