The dipole moment of phenol is smaller than that of methanol. Why?

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(N/A) In phenol, the $C-O$ bond is less polar due to the electron-withdrawing $-I$ effect of the $sp^2$ hybridized carbon of the benzene ring, which pulls the electron density away from the oxygen atom.
In methanol, the $C-O$ bond is more polar due to the electron-releasing $+I$ effect of the methyl group, which pushes electron density towards the oxygen atom.
Consequently, the net dipole moment of phenol $(\mu = 1.54 \ D)$ is smaller than that of methanol $(\mu = 1.71 \ D)$.

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Similar Questions

Picric acid is (at $25\,^{\circ}C$)

Match the following acids with their respective $pK_a$ values:
Acid$pK_a$
$(i)$ Phenol$a. 10$
$(ii)$ $p-$Nitrophenol$b. 7.1$
$(iii)$ Ethyl alcohol$c. 16$
$(iv)$ Picric acid$d. 0.78$

When phenol is treated with $D_{2}SO_{4} / D_{2}O$, some of the hydrogens get exchanged. The final product in this exchange reaction is

Assertion : Phenol is a stronger acid than ethanol.
Reason : Groups with $+M$ effect decrease acidity at $p-$position.

Which of the following statements is not correct?

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