Discuss the construction and uses of a conductivity cell.
(N/A) conductivity cell is an instrument used to measure the ionic conductivity or resistivity of an electrolytic solution.
It is available in several designs,and two simple ones are shown in the diagram.
Construction: Basically,it consists of two platinum electrodes coated with platinum black (finely divided metallic $Pt$ is deposited on the electrodes electrochemically).
These electrodes have an area of cross-section equal to $A$ and are separated by a distance $l$.
Therefore,the solution confined between these electrodes acts as a column of length $l$ and area of cross-section $A$.
Uses: By using a conductivity cell,the conductivity and resistivity of an unknown electrolytic solution can be measured.
It is available in several designs,and two simple ones are shown in the diagram.
Construction: Basically,it consists of two platinum electrodes coated with platinum black (finely divided metallic $Pt$ is deposited on the electrodes electrochemically).
These electrodes have an area of cross-section equal to $A$ and are separated by a distance $l$.
Therefore,the solution confined between these electrodes acts as a column of length $l$ and area of cross-section $A$.
Uses: By using a conductivity cell,the conductivity and resistivity of an unknown electrolytic solution can be measured.
Explore More
Similar Questions
The electrical conductance of unit volume $(1 \ cm^3)$ of solution is called as
An aqueous solution of $X$ is added slowly to an aqueous solution of $Y$ as shown in List-$I$. The variation in conductivity of these reactions is given in List-$II$. Match List-$I$ with List-$II$ and select the correct answer using the code given below the lists :
List-$I$ List-$II$ $P$. $\underset{X}{(C_2H_5)_3N} + \underset{Y}{CH_3COOH}$ $1$. Conductivity decreases and then increases $Q$. $\underset{X}{KI (0.1 \ M)} + \underset{Y}{AgNO_3 (0.01 \ M)}$ $2$. Conductivity decreases and then does not change much $R$. $\underset{X}{CH_3COOH} + \underset{Y}{KOH}$ $3$. Conductivity increases and then does not change much $S$. $\underset{X}{NaOH} + \underset{Y}{HI}$ $4$. Conductivity does not change much and then increases
Codes: $P \quad Q \quad R \quad S$
| List-$I$ | List-$II$ |
|---|---|
| $P$. $\underset{X}{(C_2H_5)_3N} + \underset{Y}{CH_3COOH}$ | $1$. Conductivity decreases and then increases |
| $Q$. $\underset{X}{KI (0.1 \ M)} + \underset{Y}{AgNO_3 (0.01 \ M)}$ | $2$. Conductivity decreases and then does not change much |
| $R$. $\underset{X}{CH_3COOH} + \underset{Y}{KOH}$ | $3$. Conductivity increases and then does not change much |
| $S$. $\underset{X}{NaOH} + \underset{Y}{HI}$ | $4$. Conductivity does not change much and then increases |
Codes: $P \quad Q \quad R \quad S$
Given that $\Lambda_{m}^{\infty} = 133.4 \, S \, cm^{2} \, mol^{-1} (AgNO_{3})$; $\Lambda_{m}^{\infty} = 149.9 \, S \, cm^{2} \, mol^{-1} (KCl)$ and $\Lambda_{m}^{\infty} = 144.9 \, S \, cm^{2} \, mol^{-1} (KNO_{3})$,the molar conductivity at infinite dilution for $AgCl$ is $....... \, S \, cm^{2} \, mol^{-1}$.
If the conductivity of $0.08 \ M$ $KCl$ solution is $2 \times 10^{-2} \ \Omega^{-1} \ cm^{-1}$,what is the molar conductivity of the solution?
If $X$ is the specific resistance (resistivity) of the solution and $M$ is the molarity of the solution,the molar conductivity of the solution is given by:
Difficult
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo