What is the distance between two successive n | vedclass

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(C) In a $DNA$ double helix structure,the two strands are coiled in a right-handed fashion.The pitch of the helix is $34\ \mathring{A}$ $(3.4\ nm)$.Th

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$3.4\ \mathring{A}$

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(C) In a $DNA$ double helix structure,the two strands are coiled in a right-handed fashion.The pitch of the helix is $34\ \mathring{A}$ $(3.4\ nm)$.There are roughly $10$ base pairs in each turn of the helix.Therefore,the distance between two successive base pairs is calculated as $34\ \mathring{A} / 10 = 3.4\ \mathring{A}$.

What is the distance between two successive nitrogen base pairs in a $DNA$ double helix?

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