Draw $\overline{AB}$ of length $10 \,cm$ and divide it in the ratio $3:8$ from $A$. Write the steps of construction.
(N/A) Steps of construction:
$1$. Draw a line segment $\overline{AB}$ of length $10 \,cm$ using a ruler.
$2$. Draw any ray $AX$ making an acute angle with $\overline{AB}$.
$3$. Locate $3 + 8 = 11$ points $A_1, A_2, ..., A_{11}$ on ray $AX$ such that $AA_1 = A_1A_2 = ... = A_{10}A_{11}$.
$4$. Join $B$ to $A_{11}$.
$5$. Through the point $A_3$,draw a line parallel to $A_{11}B$ (by making an angle equal to $\angle AA_{11}B$) intersecting $\overline{AB}$ at point $P$.
$6$. Thus,$P$ is the point dividing $\overline{AB}$ in the ratio $3:8$.
$1$. Draw a line segment $\overline{AB}$ of length $10 \,cm$ using a ruler.
$2$. Draw any ray $AX$ making an acute angle with $\overline{AB}$.
$3$. Locate $3 + 8 = 11$ points $A_1, A_2, ..., A_{11}$ on ray $AX$ such that $AA_1 = A_1A_2 = ... = A_{10}A_{11}$.
$4$. Join $B$ to $A_{11}$.
$5$. Through the point $A_3$,draw a line parallel to $A_{11}B$ (by making an angle equal to $\angle AA_{11}B$) intersecting $\overline{AB}$ at point $P$.
$6$. Thus,$P$ is the point dividing $\overline{AB}$ in the ratio $3:8$.
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