Draw the graphs of the pair of linear equatio | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $1$. For the equation $x+y=10$,if $x=0, y=10$; if $y=0, x=10$. The line passes through $(0,10)$ and $(10,0)$.$2$. For the equation $x-y=4$,if $x=0

Vedclass · Accepted Answer

$(7,3), (4,0), (10,0)$

Vedclass · Answer

(C) $1$. For the equation $x+y=10$,if $x=0, y=10$; if $y=0, x=10$. The line passes through $(0,10)$ and $(10,0)$.$2$. For the equation $x-y=4$,if $x=0, y=-4$; if $y=0, x=4$. The line passes through $(0,-4)$ and $(4,0)$.$3$. Solving the equations simultaneously: Adding $(x+y=10)$ and $(x-y=4)$ gives $2x=14$,so $x=7$. Substituting $x=7$ into $x+y=10$ gives $y=3$. The intersection point is $(7,3)$.$4$. The triangle is formed by the intersection of the two lines $(7,3)$ and their respective intersections with the $X$-axis,which are $(4,0)$ and $(10,0)$.$5$. Thus,the vertices of the triangle are $(7,3), (4,0),$ and $(10,0)$.

Draw the graphs of the pair of linear equations $x+y=10$ and $x-y=4$. Determine the coordinates of the vertices of the triangle formed by these linear equations and the $X$-axis.

Similar Questions

The general form of a linear equation in two variables is .......... (where,$a^{2}+b^{2} \neq 0$).

If $7x - 9y = 25$ and $9x - 7y = 23$,then $x + y = \dots$

Are the following pair of linear equations consistent? Justify your answer.
$-3x - 4y = 12$
$3x + 4y = 12$

$A$ pair of linear equations which has a unique solution $x=2, y=-3$ is

If in a rectangle,the length is increased and breadth reduced each by $2$ units,the area is reduced by $28$ square units. If,however,the length is reduced by $1$ unit and the breadth increased by $2$ units,the area increases by $33$ square units. Find the area of the rectangle.

Vedclass Test Series

Exam Paper Generator

Online Exam Module