Due to the Doppler effect,the shift in wavele | vedclass

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(C) The formula for the Doppler shift in wavelength for light is given by $\frac{\Delta \lambda}{\lambda} = \frac{v}{c}$,where $\Delta \lambda$ is the

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(C) The formula for the Doppler shift in wavelength for light is given by $\frac{\Delta \lambda}{\lambda} = \frac{v}{c}$,where $\Delta \lambda$ is the shift in wavelength,$\lambda$ is the original wavelength,$v$ is the velocity of the source,and $c$ is the speed of light $(3 	imes 10^8\; m/s)$.Given: $\Delta \lambda = 0.1\;\mathring{A}$,$\lambda = 6000\;\mathring{A}$,and $c = 3 	imes 10^8\; m/s$.Substituting the values into the formula:$\frac{0.1}{6000} = \frac{v}{3 	imes 10^8}$$v = \frac{0.1 	imes 3 	imes 10^8}{6000}$$v = \frac{0.3 	imes 10^8}{6000} = \frac{3 	imes 10^7}{6 	imes 10^3} = 0.5 	imes 10^4\; m/s = 5000\; m/s$.Converting to $km/s$:$v = 5\; km/s$.

Due to the Doppler effect,the shift in wavelength observed is $0.1\;\mathring{A}$,for a star producing a wavelength of $6000\;\mathring{A}$. The velocity of recession of the star will be ....... $km/s$.

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