During the detection of phosphorus in an orga | vedclass

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(C) The organic compound is fused with sodium peroxide $(Na_2O_2)$. The fused mass is then extracted with water.The aqueous solution obtained is boile

Vedclass · Accepted Answer

$(NH_4)_3PO_4 \cdot 12MoO_3$

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(C) The organic compound is fused with sodium peroxide $(Na_2O_2)$. The fused mass is then extracted with water.The aqueous solution obtained is boiled with concentrated nitric acid $(HNO_3)$,and ammonium molybdate solution is added to it.$A$ yellow precipitate indicates the presence of phosphorus in the organic compound.The chemical reaction is:$Na_3PO_4 + 12(NH_4)_2MoO_4 + 21HNO_3 \rightarrow (NH_4)_3PO_4 \cdot 12MoO_3 + 21NH_4NO_3 + 12H_2O$The yellow precipitate is ammonium phosphomolybdate,which is $(NH_4)_3PO_4 \cdot 12MoO_3$.

During the detection of phosphorus in an organic compound,a yellow precipitate is formed due to the formation of:

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