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(D) For an adiabatic process,the heat exchange $dQ = 0$.According to the first law of thermodynamics,$dQ = dU + dW$,where $dU$ is the change in intern

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$-2$

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(D) For an adiabatic process,the heat exchange $dQ = 0$.According to the first law of thermodynamics,$dQ = dU + dW$,where $dU$ is the change in internal energy and $dW$ is the work done by the gas.Given that the internal energy decreases by $2 \ J$,we have $dU = -2 \ J$.Substituting these values into the first law equation: $0 = -2 \ J + dW$.This gives $dW = 2 \ J$,which is the work done $BY$ the gas.The question asks for the work done $ON$ the gas.Work done $ON$ the gas $= -dW = -2 \ J$.

During the adiabatic expansion of $2$ moles of a gas,the internal energy of the gas is found to decrease by $2 \ J$. The work done during the process on the gas will be equal to ....... $J$.

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