During the conversion of peroxide ion (O_2^{2 | vedclass

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(C) According to Molecular Orbital Theory $(MOT)$: The electronic configuration of the peroxide ion $(O_2^{2-})$ is: $\sigma_{1s}^2 \sigma_{1s}^{*2} \

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$\pi_{2py}^*$

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(C) According to Molecular Orbital Theory $(MOT)$: The electronic configuration of the peroxide ion $(O_2^{2-})$ is: $\sigma_{1s}^2 \sigma_{1s}^{*2} \sigma_{2s}^2 \sigma_{2s}^{*2} \sigma_{2pz}^2 \pi_{2px}^2 \pi_{2py}^2 \pi_{2px}^{*2} \pi_{2py}^{*2}$. When $O_2^{2-}$ is converted to $O_2^-$,one electron is removed from the highest occupied molecular orbital,which is the antibonding $\pi^*$ orbital. Therefore,the electron is removed from $\pi_{2py}^*$ (or $\pi_{2px}^*$).

During the conversion of peroxide ion $(O_2^{2-})$ to superoxide ion $(O_2^-)$,an electron is removed from which of the following molecular orbitals?

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