During the free expansion of an ideal gas,its | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) For the free expansion of an ideal gas into a vacuum,the external pressure $P_{ext} = 0$. According to the first law of thermodynamics,$q = 0$ (ad

Vedclass · Accepted Answer

Enthalpy remains unaffected.

Vedclass · Answer

(C) For the free expansion of an ideal gas into a vacuum,the external pressure $P_{ext} = 0$. According to the first law of thermodynamics,$q = 0$ (adiabatic) and $w = -P_{ext} \Delta V = 0$. Therefore,the change in internal energy $\Delta U = q + w = 0$. Since the internal energy of an ideal gas depends only on temperature,$\Delta U = 0$ implies $\Delta T = 0$. Enthalpy is defined as $H = U + PV$. For an ideal gas,$H = U + nRT$. Since $\Delta U = 0$ and $\Delta T = 0$,the change in enthalpy $\Delta H = \Delta U + nR\Delta T = 0 + 0 = 0$. Thus,the enthalpy remains unaffected.

During the free expansion of an ideal gas,its.......

Similar Questions

For the combustion of sucrose $(C_{12}H_{22}O_{11})$ at $250\,^oC$,which of the following is true?

The volume of an ideal gas contracts from $10.0 \ L$ to $2.0 \ L$ under an applied pressure of $2.0 \ atm$. During contraction,the system also evolved $900 \ J$ of heat. The change in internal energy (in $J$) involved in the system is $(1 \ L \ atm = 101.3 \ J)$:

For which reaction is $\Delta H \neq \Delta U$?

An isolated chamber is divided into two halves by a partition,with an ideal gas in one half. By making a hole in the partition,the gas is allowed to expand to the full chamber. Among the following,the parameter which changes in the process is

The conservation of mass and energy is demonstrated by:

Vedclass Test Series

Exam Paper Generator

Online Exam Module