During the transmission of a nerve impulse th | vedclass

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(D) The correct answer is $D$.$1$. At the resting state,the inner side of the axonal membrane is negatively charged relative to the outer side due to

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First negative,then positive and again back to negative.

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(D) The correct answer is $D$.$1$. At the resting state,the inner side of the axonal membrane is negatively charged relative to the outer side due to the differential permeability of the membrane to $K^+$ and $Na^+$ ions.$2$. When a stimulus is applied,the membrane becomes permeable to $Na^+$ ions,causing an influx of $Na^+$. This leads to depolarization,where the inner side becomes positively charged.$3$. Subsequently,the membrane becomes permeable to $K^+$ ions,which move out,leading to repolarization,where the inner side returns to its original negative state.$4$. Thus,the potential changes from negative to positive and back to negative during the transmission of an action potential.

During the transmission of a nerve impulse through a nerve fibre,the potential on the inner side of the plasma membrane has which type of electric change?

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