Each element in the finite chain of resistors | vedclass

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(B) Let the potential across the last resistor be $V_4 = 2\,V$ (since $I = 1\,A$ and $R = 2\,\Omega$ is not correct,let's re-evaluate based on the cir

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$34$

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(B) Let the potential across the last resistor be $V_4 = 2\,V$ (since $I = 1\,A$ and $R = 2\,\Omega$ is not correct,let's re-evaluate based on the circuit). Looking at the circuit from right to left: $1$. The last vertical resistor has $1\,A$ flowing through it. Since $R = 1\,\Omega$,the voltage across it is $V_1 = 1\,A 	imes 1\,\Omega = 1\,V$. $2$. The current through the last horizontal resistor is $1\,A$. The voltage drop across it is $1\,A 	imes 1\,\Omega = 1\,V$. $3$. The voltage at the node before the last vertical resistor is $1\,V + 1\,V = 2\,V$. $4$. The current through the second-to-last vertical resistor is $I = V/R = 2\,V / 1\,\Omega = 2\,A$. $5$. The total current through the second-to-last horizontal resistor is $1\,A + 2\,A = 3\,A$. $6$. The voltage drop across this horizontal resistor is $3\,A 	imes 1\,\Omega = 3\,V$. $7$. The voltage at the next node is $2\,V + 3\,V = 5\,V$. $8$. The current through the third-to-last vertical resistor is $5\,V / 1\,\Omega = 5\,A$. $9$. The total current through the third-to-last horizontal resistor is $3\,A + 5\,A = 8\,A$. $10$. The voltage drop across this horizontal resistor is $8\,A 	imes 1\,\Omega = 8\,V$. $11$. The voltage at the input node is $5\,V + 8\,V = 13\,V$. $12$. The current through the first vertical resistor is $13\,A$. $13$. The total current through the first horizontal resistor is $8\,A + 13\,A = 21\,A$. $14$. The voltage drop across the first horizontal resistor is $21\,A 	imes 1\,\Omega = 21\,V$. $15$. The total input voltage is $13\,V + 21\,V = 34\,V$.

Each element in the finite chain of resistors shown in the figure is $1\,\Omega$. $A$ current of $1\,A$ flows through the final element. What is the potential difference $V$ across the input terminals of the chain in $volt$?

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