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(C) The original alphabet series is $A$ to $Z$.When written in reverse order,the series becomes: $Z, Y, X, W, V, U, T, S, R, Q, P, O, N, M, L, K, J, I

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$O$

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(C) The original alphabet series is $A$ to $Z$.When written in reverse order,the series becomes: $Z, Y, X, W, V, U, T, S, R, Q, P, O, N, M, L, K, J, I, H, G, F, E, D, C, B, A$.The eighth letter from the right in the reversed series is the same as the eighth letter from the left in the original series,which is $H$.To find the seventh letter to the left of the eighth letter from the right $(H)$,we count $7$ positions to the left of $H$ in the reversed series.Counting $7$ positions to the left of $H$ ($8^{th}$ letter): $1^{st}$ is $G$,$2^{nd}$ is $F$,$3^{rd}$ is $E$,$4^{th}$ is $D$,$5^{th}$ is $C$,$6^{th}$ is $B$,$7^{th}$ is $A$.Wait,let us re-evaluate: The eighth letter from the right in the reversed series is $H$. The seventh letter to the left of $H$ is $H + 7 = 15^{th}$ letter from the right.In the reversed series,the $15^{th}$ letter from the right is the $15^{th}$ letter from the left in the original series,which is $O$.

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