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(A) The given problem represents a mixed grouping of cells.Let $n$ be the number of cells in each row and $m$ be the number of rows.Given: $n = 5000$,

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$1.5$

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(A) The given problem represents a mixed grouping of cells.Let $n$ be the number of cells in each row and $m$ be the number of rows.Given: $n = 5000$,$m = 100$,$E = 0.15\, V$,$r = 0.25\,\Omega$,and external resistance $R = 500\,\Omega$.The total emf of the arrangement is $E_{eq} = nE = 5000 	imes 0.15 = 750\, V$.The total internal resistance of the arrangement is $r_{eq} = \frac{nr}{m} = \frac{5000 	imes 0.25}{100} = 50 	imes 0.25 = 12.5\,\Omega$.The total current $i$ in the circuit is given by $i = \frac{E_{eq}}{R + r_{eq}}$.Substituting the values: $i = \frac{750}{500 + 12.5} = \frac{750}{512.5} \approx 1.463\, A$.Rounding to the nearest option,the current is approximately $1.5\, A$.

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