The effective atomic number (EAN) of iron in | vedclass

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(C) The brown ring complex is $[Fe(H_2O)_5(NO)]SO_4$,which contains the complex ion $[Fe(H_2O)_5(NO)]^{2+}$.In this complex,the oxidation state of $Fe

Vedclass · Accepted Answer

$37$

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(C) The brown ring complex is $[Fe(H_2O)_5(NO)]SO_4$,which contains the complex ion $[Fe(H_2O)_5(NO)]^{2+}$.In this complex,the oxidation state of $Fe$ is $+1$ (since $H_2O$ is neutral and $NO$ acts as $NO^+$).The atomic number of $Fe$ is $26$.The number of electrons in $Fe^+$ is $26 - 1 = 25$.The complex has $5$ $H_2O$ ligands ($5 	imes 2 = 10$ electrons) and $1$ $NO^+$ ligand ($2$ electrons).$EAN = 25 + 10 + 2 = 37$.

The effective atomic number $(EAN)$ of iron in the brown ring complex is:

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