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(C) The charge $-2q$ at corner $C$ can be considered as two charges of $-q$ each. We can form two electric dipoles: one from charge $+q$ at $A$ and $-

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$\sqrt{3}ql$

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(C) The charge $-2q$ at corner $C$ can be considered as two charges of $-q$ each. We can form two electric dipoles: one from charge $+q$ at $A$ and $-q$ at $C$,and another from charge $+q$ at $B$ and $-q$ at $C$. The dipole moment of each dipole is $p = ql$. The angle between these two dipole vectors is $60^\circ$ (the angle of the equilateral triangle). The magnitude of the net dipole moment is given by the vector sum: $p_{net} = \sqrt{p^2 + p^2 + 2pp \cos 60^\circ}$ $p_{net} = \sqrt{2p^2 + 2p^2(1/2)} = \sqrt{3p^2} = \sqrt{3}p$ Substituting $p = ql$,we get $p_{net} = \sqrt{3}ql$.

List-$I$	List-$II$
$(A)$ Electron deficient hydride	$(I)$ $CH_4$
$(B)$ Electron precise hydride	$(II)$ $B_2H_6$
$(C)$ Electron rich hydride	$(III)$ $CaH_2$
$(D)$ Saline hydride	$(IV)$ $NiH_{0.6}$
	$(V)$ $PH_3$

Electric charges $q, q, -2q$ are placed at the corners of an equilateral triangle $ABC$ of side $l$. The magnitude of the electric dipole moment of the system is

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List-$I$ List-$II$

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$(D)$ Saline hydride $(IV)$ $NiH_{0.6}$

$(V)$ $PH_3$

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