Electric field at a distance r from an infini | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The electric field $E_1$ at a distance $r$ from an infinitely long straight wire with linear charge density $\lambda$ is given by the formula: $E_

Vedclass · Accepted Answer

$E_1 = E_2$

Vedclass · Answer

(C) The electric field $E_1$ at a distance $r$ from an infinitely long straight wire with linear charge density $\lambda$ is given by the formula: $E_1 = \frac{\lambda}{2 \pi \epsilon_0 r} = \frac{2 k \lambda}{r}$,where $k = \frac{1}{4 \pi \epsilon_0}$.The electric field $E_2$ at the centre of a semicircular arc of radius $r$ with linear charge density $\lambda$ is calculated by integrating the field components: $E_2 = \frac{2 k \lambda}{r}$.Comparing the two expressions,we find that $E_1 = \frac{2 k \lambda}{r}$ and $E_2 = \frac{2 k \lambda}{r}$.Therefore,$E_1 = E_2$.

Similar Questions

Two charges $+Q$ and $-2 Q$ are located at points $A$ and $B$ on a horizontal line as shown below. The electric field is zero at a point which is located at a finite distance:

The figure shows some electric field lines corresponding to an electric field. Then:

Four charges $q, 2q, -4q$ and $2q$ are placed in order at the four corners of a square of side $b$. The net field at the centre of the square is

Two infinitely long parallel wires have linear charge densities $\lambda_1$ and $\lambda_2$ respectively. They are placed at a distance $R$ apart. The force per unit length on the wires will be ......

Vedclass Test Series

Exam Paper Generator

Online Exam Module