Electrons accelerated from rest by an electro | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) When electrons are accelerated through a potential of $V$ volts,the momentum $p$ gained by the electrons is $p = \sqrt{2meV}$,where $m$ is the mas

Vedclass · Accepted Answer

$0.7$

Vedclass · Answer

(B) When electrons are accelerated through a potential of $V$ volts,the momentum $p$ gained by the electrons is $p = \sqrt{2meV}$,where $m$ is the mass of the electron,$e$ is the charge,and $V$ is the potential.The de Broglie wavelength $\lambda$ associated with these electrons is $\lambda = \frac{h}{p} = \frac{h}{\sqrt{2meV}}$.The fringe width $\beta$ in a Young's double slit experiment is given by $\beta = \frac{\lambda D}{d}$,where $D$ is the distance to the screen and $d$ is the slit separation.Substituting $\lambda$,we get $\beta = \frac{hD}{d\sqrt{2meV}}$. Thus,$\beta \propto \frac{1}{\sqrt{V}}$.If the potential is doubled $(V_f = 2V_i)$,the new fringe width $\beta_f$ is $\beta_f = \frac{\beta_i}{\sqrt{2}} = \frac{\omega}{\sqrt{2}} \approx 0.707\omega$.Therefore,the width is close to $0.7\omega$.

Electrons accelerated from rest by an electrostatic potential are collimated and sent through a Young's double slit experiment. The fringe width is $\omega$. If the accelerating potential is doubled,then the width is now close to ............. $\omega$.

Similar Questions

Two coherent sources $O_1$ and $O_2$ in Young's double slit experiment are illuminated with monochromatic light of wavelength $5000 \text{ Å}$. If a second order dark fringe is formed at a point $R$ on the screen,the path difference $O_1 R \sim O_2 R$ is (in $\mu m$)

In a Young's double slit experiment,$12$ fringes are observed to be formed in a certain segment of the screen when light of wavelength $600 \ nm$ is used. If the wavelength of light is changed to $400 \ nm$,the number of fringes observed in the same segment of the screen is:

In a Young's double-slit experiment,$D$ is the distance of the screen from the slits and $d$ is the separation between the slits. The distance of the nearest point to the central maximum where the intensity is the same as that due to a single slit is equal to:

When the distance between the slits is increased $4$ times in $YDSE$,the fringe width will

In a Young's experiment,two coherent sources are placed $0.90 \, mm$ apart and the fringes are observed one metre away. If it produces the second dark fringe at a distance of $1 \, mm$ from the central fringe,the wavelength of monochromatic light used would be

Vedclass Test Series

Exam Paper Generator

Online Exam Module