Electrons ejected from the surface of a metal | vedclass

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Question

(C) Einstein's photoelectric equation is given by:$h 
u = h 
u_0 + K_{max}$Since the stopping potential $V_0 = 3 \ V$,the maximum kinetic energy $K_

Vedclass · Accepted Answer

$13.5 	imes 10^{14}$

Vedclass · Answer

(C) Einstein's photoelectric equation is given by:$h 
u = h 
u_0 + K_{max}$Since the stopping potential $V_0 = 3 \ V$,the maximum kinetic energy $K_{max} = e V_0 = 1.6 	imes 10^{-19} 	imes 3 \ J$.The threshold frequency $
u_0 = 6 	imes 10^{14} \ s^{-1}$.Substituting these into the equation:$h 
u = h 
u_0 + e V_0$$
u = 
u_0 + \frac{e V_0}{h}$$
u = 6 	imes 10^{14} + \frac{1.6 	imes 10^{-19} 	imes 3}{6.4 	imes 10^{-34}}$$
u = 6 	imes 10^{14} + \frac{4.8 	imes 10^{-19}}{6.4 	imes 10^{-34}}$$
u = 6 	imes 10^{14} + 0.75 	imes 10^{15}$$
u = 6 	imes 10^{14} + 7.5 	imes 10^{14} = 13.5 	imes 10^{14} \ s^{-1}$.

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