Emission of a $\beta$-particle by an atom of an element results in the formation of its

$A$ radioactive substance $_{88}X^{228}$ $(IIA)$ emits $3$ $\alpha$ and $3$ $\beta$ particles to form $Y$. To which group of the long form of the periodic table does $Y$ belong?

When a radioactive element emits an alpha particle,the daughter element is placed in the periodic table:

$A$ nuclide of an alkaline earth metal undergoes radioactive decay by emission of two $\alpha$-particles in succession. The group of the periodic table to which the resulting daughter element would belong is $Group$ .......

$Nd$ $(Z = 60)$ is a member of group $3$ in the periodic table. An isotope of it is $\beta$-active. The daughter nuclei will be a member of Group $...$ ...

$_{84}Po^{210} \xrightarrow{} _{82}Pb^{206} + _{2}He^{4}$. From the above equation,deduce the position of polonium in the periodic table (lead belongs to group $IV A$).