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(B) The power $P$ of a nuclear reactor is given by the product of the fission rate $R$ and the energy released per fission $E$.$P = R 	imes E$Given:$

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$10^{15} / s$

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(B) The power $P$ of a nuclear reactor is given by the product of the fission rate $R$ and the energy released per fission $E$.$P = R 	imes E$Given:$P = 32 \ kW = 32 	imes 10^3 \ W$$E = 200 \ MeV = 200 	imes 10^6 \ eV = 200 	imes 10^6 	imes 1.6 	imes 10^{-19} \ J$Substituting these values into the formula:$32 	imes 10^3 = R 	imes (200 	imes 10^6 	imes 1.6 	imes 10^{-19})$$R = \frac{32 	imes 10^3}{320 	imes 10^{-13}}$$R = \frac{32 	imes 10^3}{3.2 	imes 10^{-11}}$$R = 10^{15} / s$

Energy released in the fission of a single ${ }_{92} U^{235}$ nucleus is $200 \ MeV$. The fission rate of a ${ }_{92} U^{235}$ fuelled reactor operating at a power level of $32 \ kW$ is:

Similar Questions

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