(A) The energy $U$ stored in an inductor with self-inductance $L$ carrying a current $I$ is given by the formula: $U = \frac{1}{2} LI^2$ Given: $L = 2

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(A) The energy $U$ stored in an inductor with self-inductance $L$ carrying a current $I$ is given by the formula: $U = \frac{1}{2} LI^2$ Given: $L = 200 \ mH = 200 \times 10^{-3} \ H = 0.2 \ H$ $I = 4 \ A$ Substituting the values into the formula: $U = \frac{1}{2} \times 0.2 \times (4)^2$ $U = 0.1 \times 16$ $U = 1.6 \ J$ Therefore,the energy required is $1.6 \ J$.

Class 12 Physics Electromagnetic Induction Energy Stored in Inductor

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Energy required to establish a current of $4 \ A$ in a coil of self-inductance $L = 200 \ mH$ is . . . . . . . (in $J$)

GUJCET 2010 All GUJCET

A
$1.6$
B
$0.40$
C
$0.18$
D
$0.16$

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Electromagnetic Induction

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Energy Stored in Inductor

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Energy required to establish a current of $4 \ A$ in a coil of self-inductance $L = 200 \ mH$ is . . . . . . . (in $J$)

Similar Questions

In the figure, the magnetic energy stored in the coil is:

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If the current through an inductor increases from $2 \ A$ to $3 \ A$,the magnetic energy stored in the inductor increases by: (in $\%$)

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