Energy required to remove an electron from an aluminum surface is $4.2 \text{ eV}$. If light of wavelength $2000 \text{ Å}$ falls on the surface,the velocity of the fastest electron ejected from the surface will be:

  • A
    $8.4 \times 10^5 \text{ m/s}$
  • B
    $7.4 \times 10^5 \text{ m/s}$
  • C
    $6.4 \times 10^5 \text{ m/s}$
  • D
    $8.4 \times 10^6 \text{ m/s}$

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