Equal volumes of 0.002 , M solutions of sodiu | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) When equal volumes of sodium iodate and cupric chlorate solutions are mixed,the concentration of each species is halved,becoming $0.001 \, M$.$NaI

Vedclass · Accepted Answer

No,precipitation will not occur.

Vedclass · Answer

(B) When equal volumes of sodium iodate and cupric chlorate solutions are mixed,the concentration of each species is halved,becoming $0.001 \, M$.$NaIO_3 ightarrow Na^{+} + IO_3^{-}$$[IO_3^{-}] = 0.001 \, M$$Cu(ClO_3)_2 ightarrow Cu^{2+} + 2ClO_3^{-}$$[Cu^{2+}] = 0.001 \, M$The ionic product $(Q_{sp})$ for $Cu(IO_3)_2$ is calculated as:$Q_{sp} = [Cu^{2+}][IO_3^{-}]^2$$Q_{sp} = (0.001) 	imes (0.001)^2$$Q_{sp} = 10^{-3} 	imes 10^{-6} = 10^{-9}$Since $Q_{sp} (1 	imes 10^{-9}) Therefore,precipitation will not occur.

Equal volumes of $0.002 \, M$ solutions of sodium iodate and cupric chlorate are mixed together. Will it lead to precipitation of copper iodate?
(For cupric iodate $K_{sp} = 7.4 \times 10^{-8}$)

Similar Questions

Which of the following reagents can dissolve the precipitate of $HgS\,\downarrow$?

The $K_{sp}$ of an electrolyte $AB$ is $1 \times 10^{-10}$. If $[A^{+}] = 10^{-5} \ M$,which concentration of $B^{-}$ will not result in the precipitation of $AB$?

The required amount of $KBr$ (molar mass $= 119 \ g/mol$) in grams to start the precipitation of $AgBr$ in $500 \ mL$ solution of $0.05 \ M \ AgNO_3$ will be :- ($K_{SP}$ of $AgBr = 5 \times 10^{-13}$)

If the solubility product of $AgCl$ is $10^{-10}$,what is the solubility of $AgCl$ in $0.001 \ M \ NaCl$?

The solubility of $CaCO_3$ is $7 \times 10^{-5} \ mol \ dm^{-3}$ at $25^{\circ} C$. What is its solubility product at same temperature?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Equal volumes of $0.002 \, M$ solutions of sodium iodate and cupric chlorate are mixed together. Will it lead to precipitation of copper iodate?(For cupric iodate $K_{sp} = 7.4 \times 10^{-8}$)