The equation of the straight line making equal intercepts on the axes and passing through the point $(2, 4)$ is

The equation of the line whose slope is $3$ and which cuts off an intercept of $3$ from the positive $x$-axis is

If $\alpha$ is the angle made by the perpendicular drawn from the origin to the line $12x - 5y + 13 = 0$ with the positive $X$-axis in the anti-clockwise direction,then $\alpha =$

Find the angle in degrees $(^o)$ made by the line joining the points $(1, 0)$ and $(-2, \sqrt{3})$ with the $x$-axis.

Find the equation of a straight line that makes an intercept of $3$ units on the negative direction of the $y$-axis and is inclined at an angle of ${\tan ^{ - 1}}\left( {\frac{3}{5}} \right)$ with the $x$-axis.

If each of the points $(a, 4)$ and $(-2, b)$ lies on the line joining the points $(2, -1)$ and $(5, -3)$,then the point $(a, b)$ lies on the line: