Equivalent mass of the oxidizing agent in the | vedclass

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(B) In the reaction $SO_2 + 2H_2S 	o 3S + 2H_2O$,the oxidation state of $S$ in $SO_2$ changes from $+4$ to $0$ in $S$. Thus,$SO_2$ acts as the oxidiz

Vedclass · Accepted Answer

$16$

Vedclass · Answer

(B) In the reaction $SO_2 + 2H_2S 	o 3S + 2H_2O$,the oxidation state of $S$ in $SO_2$ changes from $+4$ to $0$ in $S$. Thus,$SO_2$ acts as the oxidizing agent. The change in oxidation number per molecule of $SO_2$ is $|4 - 0| = 4$. Therefore,the $n$-factor for $SO_2$ is $4$. The molar mass $(M_W)$ of $SO_2$ is $32 + (2 	imes 16) = 64 \ g/mol$. The equivalent mass $(E)$ is given by $E = \frac{M_W}{n	ext{-factor}} = \frac{64}{4} = 16$.

Equivalent mass of the oxidizing agent in the reaction $SO_2 + 2H_2S \to 3S + 2H_2O$ is

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